Open a specific page in a PDF file c#

Question

I open a pdf file when my form is loaded with the following code:

Process process = new Process();
ProcessStartInfo startInfo = new ProcessStartInfo();
proce         


        

Answer 1

call it like what was suggested here: Adobe Reader Command Line Reference

So it would be:

    ProcessStartInfo startInfo = new ProcessStartInfo();
    startInfo.FileName = "EXE_PATH\\AcroRd32.exe";
    startInfo.Arguments = "/A \"page=PAGE_NUM\" \"FILE_PATH\"";
    Process.Start(startInfo);

Answer 2

Checkout this : http://partners.adobe.com/public/developer/en/acrobat/PDFOpenParameters.pdf

It explain what arguments Adobe Reader can receive.

And it has a Page argument.

Your code must be :

Process process = new Process();
ProcessStartInfo startInfo = new ProcessStartInfo();
process.StartInfo = startInfo;
startInfo.Arguments = "/A \"page=N\"";
startInfo.FileName = @"F:\STAGE\test.pdf";
process.Start();

Where N is your page number.

Answer 3

Try this. Note: you must have acrobat reader installed in your pc before you can use axAcroPDF .

            int n = 5; //page number
            string filePath = "F:\STAGE\test.pdf";

            axAcroPDF1.LoadFile(filePath);
            axAcroPDF1.setCurrentPage(n); 

Answer 4

you can try this code.

  Process myProcess = new Process();
  myProcess.StartInfo.FileName = @"C:\Program Files\Adobe\Reader 11.0\Reader\AcroRd32.exe";
  myProcess.StartInfo.Arguments = "/A \"page={pagenum}\" \"c:\\Classic\\Manual\\DocumentationManual.pdf\"";
  myProcess.Start();

please change the path of AcroRd32.exe as per your directory.

Thanks

Answer 5

Try

process.StartInfo.Arguments = "/A \"page=n\" \"F:\\STAGE\\test.pdf"";

changing n to the page number you want