PHP Warning: mysqli_fetch_assoc() expects exactly 1 parameter, 3 given in

Question

I get this error, I tried going through other similar threads but it didn\'t help.

here is php

$host = \"http://www.domain.com\";
$hostname = \"local         


        

Answer 1

Syntax mysqli_fetch_assoc is:

array mysqli_fetch_assoc ( mysqli_result $result )

Try (for PHP >=5.4):

$hits = mysqli_fetch_assoc($result)['hits'];

Answer 2

From the codes, I see that you want to UPDATE the final records from hits.

$hitquery =  "SELECT * FROM $userstable where url = '$url'";
$result = mysqli_query($con, $hitquery);
while(null !== ($hits= mysqli_fetch_assoc($result))) {
    $query2 = "UPDATE $userstable SET `hits` = hits+1 where url = '$url'";
}