Renaming single file names while copying entire folder using copyTpl

Question

My yeoman generator copies files from template to destination path:

this.fs.copyTpl(
            this.templatePath(),
            this.destinationPath(), {
          


        

Answer 1

OK, I found a solution. According to yeoman docs:

Any generator author can register a transformStream to modify the file path and/or the content.

Using this method:

this.registerTransformStream();

What that means is I can pipe all generated files through some script:

var rename = require("gulp-rename");
//other dependecies...

module.exports = yeoman.Base.extend({

    //some other things generator do...

    writing: function() {
        var THAT = this;
        this.registerTransformStream(rename(function(path) {
            path.basename = path.basename.replace(/(666replacethat666)/g, THAT.props.appName);
            path.dirname = path.dirname.replace(/(666replacethat666)/g, THAT.props.appName);
        }));
        this.fs.copyTpl(
            this.templatePath(),
            this.destinationPath(), {
                appName: this.props.appName
            });
    }
});

This script will pipe all files through gulp-rename, changing 666replacethat666 to something more intelligent.

Answer 2

registerTransformStream with gulp-rename is still an issue. However, I get it working with glob.

const glob = require('glob');

writing() {
    const files = glob.sync('**', { dot: true, nodir: true, cwd: this.templatePath() })
    for (let i in files) {
        this.fs.copyTpl(
            this.templatePath(files[i]),
            this.destinationPath( this.props.destinationFolderPath + '\\' + files[i].replace(/__fileName__/g,this.props.fileName)),
            this.props
        )
    }
}