Better solution than if __name__ == '__main__' twice in Python script

Question

I have multiple Python scripts which use docopt.

My issue is that the available options for the two scripts differ slightly - one option is present in one script, bu

Answer 1

The clean solution is to refactor your code so it doesn't rely on a global, neither in main.py nor module1.py:

"""
main.py

Usage:
    main.py [--num=<num>] [--name=<name>]
    main.py -h | --help
    main.py --version

Options:
    --num=<num>  A number
    --name=<name>  A name
    --version
"""
from other_file import x, y
from module1 import function


def main(num):
    print 'In main()'
    function(num)
    print num


if __name__ == '__main__':
    import docopt

    arguments = docopt.docopt(__doc__, version=0.1)
    NUM = arguments['--num']

    print '{} being executed directly'.format(__name__)
    main(NUM)

And:

"""
module1.py

Usage:
    module1.py [--num=<num>]
    module1.py -h | --help
    module1.py --version

Options:
    --num=<num>  A number
    --version
"""
from other_file import z


def main(num):
    print 'In main()'
    print num


def function(num):
    print 'In function in {}'.format(__name__)
    print num


if __name__ == '__main__':
    import docopt

    arguments = docopt.docopt(__doc__, version=0.1)
    NUM = arguments['--num']

    print '{} being executed directly'.format(__name__)
    main(NUM)