Dynamic instance attributes

Question

Say i have a class:

class Foo(object):
    def __init__(self,d):
        self.d=d

d={\'a\':1,\'b\':2}

inst=Foo(d)

inst.d
Out[315]: {\'a\': 1, \'b\': 2}


        

Answer 1

Here is a solution even more outlandish than the one offered by pythonm:

class Foo(object):
    def __init__(self, d):
        self.__dict__ = d

Instead of using inst.d, use inst.__dict__ directly. An added benefit is that new keys added to d automatically become attributes. That's as dynamic as it gets.

Answer 2

use setattr():

>>> class foo(object):
    def __init__(self, d):
        self.d = d
        for x in self.d:
            setattr(self, x, self.d[x])


>>> d = {'a': 1, 'b': 2}
>>> l = foo(d)
>>> l.d
{'a': 1, 'b': 2}
>>> l.a
1
>>> l.b
2
>>> 

Answer 3

class Foo(object):
    def __init__(self, attributes):
        self.__dict__.update(attributes)

That would do it.

>>>foo = Foo({'a': 42, 'b': 999})
>>>foo.a
42
>>>foo.b
999

You can also use the setattr built-in method:

class Foo(object):
    def __init__(self, attributes):
        for attr, value in attributes.iteritems():
            setattr(self, attr, value)

Answer 4

You can also use __getattr__.

class Foo(object):

    def __init__(self, d):
        self.d = d

    def __getattr__(self, name):
        return self.d[name]

Answer 5

You could do something like this:

class Foo(object):
    def __init__(self, **kwdargs):
        self.__dict__.update(kwdargs)

d = {'a':1,'b':2}

foo = Foo(**d)
foo2 = Foo(a=1, b=2)