C# How to extract complete xml node set

Question

Answer 1

Let's say this XML is stored in an XmlDocument called doc.

XmlElement docRoot = doc.DocumentElement;
XmlNode cookingNode = docRoot.SelectSingleNode("./book[@category='COOKING']");

I tested this and added this line to verify:

Console.WriteLine(cookingNode.OuterXml);

Here was the output:

<book category="COOKING"><title lang="en">Everyday Italian</title><author>Giada
De Laurentiis</author><year>2005</year><price>30.00</price></book>

Answer 2

This query will select that node. Are you trying to get a set of nodes or just the single one? You might have to put the bookstore node back yourself if you only want th subset of nodes.

/bookstore/book[@category='COOKING']

as XmlDocument ...

var x = new XmlDocument();
x.Load("XmlFile1.xml");
var ns = x.SelectSingleNode("/bookstore/book[@category='COOKING']");

var res = ns.OuterXml;

as XDocument ...

var x = XDocument.Load("XmlFile1.xml");

var root = new XElement("bookstore",
    from book in x.Element("bookstore").Elements("book")
    where book.Attribute("category").Value == "COOKING"
    select book
    );

if you just want the book node you can do this instead of the root version above

var book = x.Element("bookstore")
    .Elements("book")
    .Where(n => n.Attribute("category").Value == "COOKING")
    .First();

Answer 3

Adding to Matthew's response:

XmlDocument xDoc = new XmlDocument();
// (Put code to populate xDoc here)
XmlNodeList xNode = xDoc.SelectNodes(@"/bookstore/book[@category='COOKING']");

xNode now equals Book of type COOKING.

Answer 4

suppose I want to extract only the data wherethe xml file is as follows ..

<book category="COOKING"> 
    <title lang="en">Everyday Italian</title>
    <author auth="up">Giada De Laurentiis</author>    
    <year>2005</year>
   <price>30.00</price>
  </book>

the final result on the list view should look like this

  lang       auth
  en          up

I have coded as follows ..

XmlNodeList elemList = doc.GetElementsByTagName("book");
                    for (int j = 0; j < elemList.Count; j++)
                    {
                        if (elemList[j].Attributes["category"].Value == "COOKING")
                        {
                            XmlNodeList elemList1 = doc.GetElementsByTagName("author");
                            for (int i = 0; i < elemList1.Count; i++)
                            {
                                string attrVal = elemList1[i].Attributes["lang"].Value;
                                string attrVal1 = elemList1[i].Attributes["auth"].Value;

                                ListViewItem lvi = new ListViewItem();

                                    lvi.SubItems.Add(attrVal1);
                                    lvi.SubItems.Add(attrVal1);
                                }
                                listView1.Items.Add(lvi);
                            }
                        }
                    }