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calling php function from submit button

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孤街浪徒
孤街浪徒 2021-01-15 08:51

I want to pass the value of input field address to php. So that when i click on submit button it will be store in php.
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4条回答
  • 南笙
    2021-01-15 09:27

    what you intend to do can be done as below method.

    <form method="post" >

<input type="text" name="address">
<input type="submit" name="go">

</form>



<?php
    if($_POST){
    if(isset($_POST['go'])){
    call();
    }else{
    echo "Error";
    }
    }
    function call(){
    echo "hi";
    echo $_POST['address'];
    }
?>
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  • 走了就别回头了
    2021-01-15 09:28

    You are mixing PHP and JavaScript. If you want a pure PHP solution you could do something like:

    <?php
if(isset($_POST['go'])){
     $address = $_POST['address'];
     echo $address;
}
?>

<form method="POST">
  <input type="text" name="address">
  <input type="submit" name="go" method="post">
</form>

    With PHP once the form is submitted you can access form values with $_POST so use $_POST['address'] instead of document.address.value

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  • 南旧
    2021-01-15 09:38

    use this code 

    <input type="text" name="address">
<input type="submit" name="go" method="post">
<?php
    if($_POST){
    if(isset($_POST['go'])){
    call();
    }else{
    echo "Error";
    }

    function call(){
    echo "hi";
    echo $_POST['address'];
    }
?>
    0 讨论(0)
  • 抹茶落季
    2021-01-15 09:45

    Try like this,this is working fine as per your requirement:

    <html>
<body>
<form action="" method="post">
Address: <input type="text" name="name"><br>
<input type="submit" name="go" value="call" />
</form>

<?php
if (isset($_REQUEST['name'])) {
    call();
    }
?>
<?php
function call() {
 $address= $_POST['name'];
echo "Address:".$address;
exit;
}

    Output:-

    For output Click here

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