How to split a string in sql server 2008 using stored procedure and insert the data to table

Question

I want to split a string in this format Quote:

\"date=10/10/2000|age=13^date=01/01/2001|age=12^date=02/02/2005|age=8\"

. Actually this stri

Answer 1

try this:

Declare @stringToSplit varchar(max)='date=10/10/2000|age=13^date=01/01/2001|age=12^date=02/02/2005|age=8^date=10/10/2000|age=13^date=01/01/2001|age=12^date=02/02/2005|age=8^date=10/10/2000|age=13^date=01/01/2001|age=12^date=02/02/2005|age=8^date=10/10/2000|age=13^date=01/01/2001|age=12^date=02/02/2005|age=8'

DECLARE @YourTable table (RowID int, Layout varchar(max))
INSERT @YourTable VALUES (1,@stringToSplit)

;WITH SplitSting AS
(
    SELECT
    RowID,LEFT(Layout,CHARINDEX('^',Layout)-1) AS Part
   ,RIGHT(Layout,LEN(Layout)-CHARINDEX('^',Layout)) AS Remainder
    FROM @YourTable
    WHERE Layout IS NOT NULL AND CHARINDEX('^',Layout)>0
    UNION ALL
    SELECT
    RowID,LEFT(Remainder,CHARINDEX('^',Remainder)-1)
   ,RIGHT(Remainder,LEN(Remainder)-CHARINDEX('^',Remainder))
    FROM SplitSting
    WHERE Remainder IS NOT NULL AND CHARINDEX('^',Remainder)>0
    UNION ALL
    SELECT
    RowID,Remainder,null
    FROM SplitSting
    WHERE Remainder IS NOT NULL AND CHARINDEX('^',Remainder)=0

)

select SUBSTRING(part,CHARINDEX('=',part)+1,(CHARINDEX('|',part)-CHARINDEX('=',part))-1) as [Date],RIGHT(part,CHARINDEX('=',reverse(part))-1) as [Age] from SplitSting

Answer 2

DECLARE @s VARCHAR(300)
SET @s = 'RELGENINS|1121232243434|343434343434|343434-683211|34343434.00|CIT|22297568|NA|INR|ONDIRECT|NA|NA|NA|22-03-2014 10:43:20|0300|NA|NA|NA|NA|NA|NA|NA|NA|NA|Success|1790153891'

DECLARE @tmp TABLE(   aDate varchar(50))

;WITH MyRows AS
(
    SELECT LEFT(@s, CHARINDEX('|', @s) -1) AS MyRow, RIGHT(@s, LEN(@s) - CHARINDEX('|', @s)) AS Remainder

    UNION ALL
    SELECT LEFT(Remainder, CHARINDEX('|', Remainder) -1) AS MyRow, RIGHT(Remainder, LEN(Remainder) - CHARINDEX('|', Remainder)) AS Remainder
    FROM MyRows
    WHERE CHARINDEX('|', Remainder)>0
    UNION ALL
    SELECT Remainder AS MyRow, NULL AS Remainder
    FROM MyRows
    WHERE CHARINDEX('|', Remainder)=0
)
INSERT INTO @tmp (aDate)
SELECT  SUBSTRING(MyRow, 0, 20) as date
FROM MyRows

SELECT *
FROM @tmp 

Answer 3

In general, I'd suggest to write a CLR function which split strings by regex or SQL table-valued function, but in you case you can try something simple like converting your string to xml and parsing it:

declare @str nvarchar(max) = 'date=10/10/2000|age=13^date=01/01/2001|age=12^date=02/02/2005|age=8'
declare @data xml

select @str = replace(@str, '=', '="')
select @str = replace(@str, '|', '" ')
select @str = replace(@str, '^', '"/><row ')
select @str = '<row ' + @str + '"/>'

select @data = cast(@str as xml)

select
    t.c.value('@date', 'nvarchar(max)') as [date],
    t.c.value('@age', 'nvarchar(max)') as [age]
from @data.nodes('row') as t(c)

sql fiddle demo