Copy all script arguments to another variable

Question

I need to copy all script arguments and pass them to another script. I have tried to do it like this:

args=$@    
printargs.sh $args
echo ------
printargs.sh         


        

Answer 1

$@ is like an array, so your temporary storage needs to be an array:

args=( "$@" )      # quotes are needed there

And then to use them:

printargs.sh "${args[@]}"