Longest common prefix length of all substrings and a string

Question

I found similar questions on StackOverflow, but my question is different.

Given a string s contains lowercase alphabet. I want to find the

Answer 1

This is similar to Z-algorithm for pattern matching. Except for the first case where len(LCP(s(1, 6), s)) = len (s).

We need to create a Z array . For a string str[0..n-1], Z array is of same length as string. An element Z[i] of Z array stores length of the longest substring starting from str[i] which is also a prefix of str[0..n-1]. The first entry of Z array is meaning less as complete string is always prefix of itself.

Visualize the algorithm here : https://personal.utdallas.edu/~besp/demo/John2010/z-algorithm.htm

Below is the solution of the same :

public static int[] computeZ(String s) {
    int l = 0; r = 0;
    int [] Z = new int[len];
    int len = s.length();
    for (int k =0 ; k < len; k++ ) {
        int j;
        if (k < r) {
            j = (z[k-l] < (r-k)) ? z[k-l] : (r-k)
        } else {
            j = 0;
        }
        while (k + j < len) {
            if (s.charAt(k+j) == s.charAt(j)) {
                j++;
            } else {
                break;
            }
        }
        if (k + j > r) {
            l = k;
            r = k + j;
        }
    }
    Z[0] = len;
    return Z;
}

Answer 2

As mentioned by Aditya, this can be solved using Z-Algorithm. Please find the detailed explanation with implementation here - https://www.hackerearth.com/practice/algorithms/string-algorithm/z-algorithm/tutorial/