End python code after 60 seconds

Question

Below there is some fully functioning code.

I am planning to execute this code through command line, however I would like it to end after 60 seconds.

Does an

Answer 1

This is my favorite way of doing timeout.

def timeout(func, args=None, kwargs=None, TIMEOUT=10, default=None, err=.05):
    if args is None:
        args = []
    elif hasattr(args, "__iter__") and not isinstance(args, basestring):
        args = args
    else:
        args = [args]

    kwargs = {} if kwargs is None else kwargs

    import threading
    class InterruptableThread(threading.Thread):
        def __init__(self):
            threading.Thread.__init__(self)
            self.result = None

        def run(self):
            try:
                self.result = func(*args, **kwargs)
            except:
                self.result = default

    it = InterruptableThread()
    it.start()
    it.join(TIMEOUT* (1 + err))
    if it.isAlive():
        return default
    else:
        return it.result

Answer 2

Use signal.ALARM to get notified after a specified time.

import signal, os

def handler(signum, frame):
    print '60 seconds passed, exiting'
    cleanup_and_exit_your_code()

# Set the signal handler and a 60-second alarm
signal.signal(signal.SIGALRM, handler)
signal.alarm(60)

run_your_code()

From your example it is not obvious what the code will exactly do, how it will run and what kind of loop it will iterate. But you can easily implement the ALARM signal to get notified after the timeout has expired.

Answer 3

You could move your code into a daemon thread and exit the main thread after 60 seconds:

#!/usr/bin/env python
import time
import threading

def listen():
    print("put your code here")

t = threading.Thread(target=listen)
t.daemon = True
t.start()

time.sleep(60)
# main thread exits here. Daemon threads do not survive.

Answer 4

I hope this is an easy way to execute a function periodically and end after 60 seconds:

import time
import os
i = 0
def executeSomething():
 global i
 print(i)
 i += 1
 time.sleep(1)
 if i == 10:
    print('End')
    os._exit(0)


while True:
 executeSomething()

Answer 5

Try this out:

import os
import time
from datetime import datetime
from threading import Timer

def exitfunc():
    print "Exit Time", datetime.now()
    os._exit(0)

Timer(5, exitfunc).start() # exit in 5 seconds

while True: # infinite loop, replace it with your code that you want to interrupt
    print "Current Time", datetime.now()
    time.sleep(1)

There are some more examples in this StackOverflow question: Executing periodic actions in Python

I think the use of os._exit(0) is discouraged, but I'm not sure. Something about this doesn't feel kosher. It works, though.