Converting yearmon column to last date of the month in R

前端 未结 3 1482
天命终不由人
天命终不由人 2021-01-15 03:03

I have a data frame (df) like the following:

Date        Arrivals

2014-07      100
2014-08      150
2014-09      200

I know that I can con

相关标签:
3条回答
  • 2021-01-15 03:32

    Using lubridate, you can add a month and subtract a day to get the last day of the month:

    library(lubridate)
    
    ymd(paste0(df$Date, '-01')) + months(1) - days(1)
    # [1] "2014-07-31" "2014-08-31" "2014-09-30"
    
    0 讨论(0)
  • 2021-01-15 03:35

    Here is a way to do it using the zoo package.

    R code:

    library(zoo)
    df
    #      Date Arrivals
    # 1 2014-07      100
    # 2 2014-08      150
    # 3 2014-09      200
    
    df$Date <- as.Date(as.yearmon(df$Date), frac = 1)
    
    # output
    #         Date Arrivals
    # 1 2014-07-31      100
    # 2 2014-08-31      150
    # 3 2014-09-30      200
    
    0 讨论(0)
  • 2021-01-15 03:58

    If the Date variable is an actual yearmon class vector, from the zoo package, the as.Date.yearmon method can do what you want via its argument frac.

    Using your data, and assuming that the Date was originally a character vector

    library("zoo")
    df <- data.frame(Date = c("2014-07", "2014-08", "2014-09"),
                     Arrivals = c(100, 150, 200))
    

    I convert this to a yearmon vector:

    df <- transform(df, Date2 = as.yearmon(Date))
    

    Assuming this is what you have, then you can achieve what you want using as.Date() with frac = 1:

    df <- transform(df, Date3 = as.Date(Date2, frac = 1))
    

    which gives:

    > df
         Date Arrivals    Date2      Date3
    1 2014-07      100 Jul 2014 2014-07-31
    2 2014-08      150 Aug 2014 2014-08-31
    3 2014-09      200 Sep 2014 2014-09-30
    

    That shows the individual steps. If you only want the final Date this is a one-liner

    ## assuming `Date` is a `yearmon` object
    df <- transform(df, Date = as.Date(Date, frac = 1))
    ## or if not a `yearmon`
    df <- transform(df, Date = as.Date(as.yearmon(Date), frac = 1))
    

    The argument frac in the fraction of the month to assign to the resulting dates when converting from yearmon objects to Date objects. Hence, to get the first day of the month, rather than convert to a character and paste on "-01" as your Question showed, it's better to coerce to a Date object with frac = 0.

    If the Date in your df is not a yearmon class object, then you can solve your problem by converting it to one and then using the as.Date() method as described above.

    0 讨论(0)
提交回复
热议问题