Why do you think the code below does not work? What would you change/add to make it work?
Any help is appreciated..
function TraceIt(message:String,
Ok, here is the solution.. after breaking my head : )
function TraceIt(message:String, num:int)
{
trace(message, num);
}
function aa(f:Function=null, ...args):void
{
var newArgs:Array = args as Array;
newArgs.unshift(f);
bb.apply(null, newArgs);
}
aa(TraceIt, "test", 1);
var func:Function = null;
var argum:*;
function bb(f:Function=null, ...args):void
{
func = f;
argum = args as Array;
exec();
}
function exec():void
{
if (func == null) { return; }
func.apply(this, argum);
}
This way, you can pass arguments as variables to a different function and execute them..
Thanks to everyone taking the time to help...
When TraceIt() eventually gets called, it's being called with 1 Array parameter, not a String and int parameters.
You could change TraceIt() to:
function TraceIt(args:Array)
{
trace(args[0], args[1]);
}
Or you could change exec() to:
function exec()
{
func.apply(null, argum[0].toString().split(","));
}
...as it appears when you pass "test", 1, you end up with array whose first value is "test,1". This solution doesn't work beyond the trivial case, though.
Change your bb function to look like this:
function bb(f:Function, args:Array):void
{
func = f;
argum = args;
exec();
}
As you have it now, it accepts a variable number of arguments, but you are passing in an array(of the arguments) from aa.