Extract nodes data from xml

Question

I have an xml like this:

  5
  7
  9


        

Answer 1

Try the following code:

 public DataTable GetColumnsFromXML(String XMLPath, String TableName)
{
    DataTable dtForColumns = DatatableforColumns();
    XmlDataDocument xmldoc = new XmlDataDocument();
    xmldoc.Load(XMLPath);
    XmlElement root = xmldoc.DocumentElement;
    XmlNodeList tablenodes = root.SelectNodes("Table");

    if (tablenodes != null)

        foreach (XmlNode nodes in tablenodes)
        {
            if (!nodes.HasChildNodes) continue;
            if (nodes.Attributes == null) continue;
            //TableName = nodes.Attributes[0].Value;

            if (nodes.Attributes[0].Value == TableName)
            {
                String PrimaryKey = nodes.Attributes[1].Value;
                var nodesdisplayname = nodes.SelectNodes("Column/DisplayColumn");
                var nodesorignalvalue = nodes.SelectNodes("Column/OrignalColumn");

                if (nodesdisplayname != null && nodesorignalvalue != null)
                {
                    for (int i = 0; i <= nodesdisplayname.Count - 1; i++)
                    {
                        var xmlDisplayNode = nodesdisplayname.Item(i);
                        var xmlOrignalNode = nodesorignalvalue.Item(i);


                        if (xmlDisplayNode != null && xmlOrignalNode != null)
                        {

                            DataRow dr;
                            dr = dtForColumns.NewRow();
                            dr["DisplayColumn"] = xmlDisplayNode.InnerText;
                            dr["OrignalColumn"] = xmlOrignalNode.InnerText;
                            dr["PrimaryKey"] = PrimaryKey;
                            dtForColumns.Rows.Add(dr);
                        }
                    }
                }
            }
        }
    return dtForColumns;
}
private DataTable DatatableforColumns()
{
    DataTable dt = new DataTable();
    dt.Columns.Add("DisplayColumn", typeof(String));
    dt.Columns.Add("OrignalColumn", typeof(String));
    dt.Columns.Add("PrimaryKey", typeof(String));
    return dt;
}

To Access these here is the code:

DataTable dtColumns = new DataTable();        
dtColumns = objXML.GetColumnsFromXML(Server.MapPath("~/XMLFile.xml"), TableName);

Customize it according to your requirement, hope this will work for you.

Answer 2

I don't know it is fast enough for you but I'll give it a try

string s = String.Join("," , xDoc.Descendants("PersonID").Select(p => (string)p));

Answer 3

You can use LINQ to XML with string.Join like:

XDocument xmlDoc = XDocument.Parse(@"<People>
                                      <PersonID>5</PersonID>
                                      <PersonID>7</PersonID>
                                      <PersonID>9</PersonID>
                                    </People>");
var val = xmlDoc.Descendants("People")
                 .SelectMany(r => r.Elements("PersonID"))
                 .Select(r => r.Value);
string str = string.Join(",", val);

str will be str = "5,7,9"