Regex to get all character to the right of first space?

Question

I am trying to craft a regular expression that will match all characters after (but not including) the first space in a string.

Input text:

foo bar b         


        

Answer 1

You don't need look behind.

my $str = 'now is the time';
# Non-greedily match up to the first space, and then get everything after in a group.
$str =~ /^.*? +(.+)/; 
my $right_of_space = $1; # Keep what is in the group in parens
print "[$right_of_space]\n";

Answer 2

You can also try this

(?s)(?<=\S*\s+).*

or

(?s)\S*\s+(.*)//group 1 has your match

With (?s) . would also match newlines

Answer 3

I'd prefer to use [[:blank:]] for it as it doesn't match newlines just in case we're targetting mutli's. And it's also compatible to those not supporting \s.

(?<=[[:blank:]]).*

Answer 4

You can use a positive lookbehind:

(?<=\s).*

(demo)

Although it looks like you've already put a capturing group around .* in your current regex, so you could just try grabbing that.