get a count of each value from every column in a table SQL Server

Question

So I looked this up and this question is very similar but it\'s missing a key piece: SQL Server count number of distinct values in each column of a table

So in that

Answer 1

You could use:

DECLARE @Table SYSNAME = 'TableName'; 
DECLARE @SQL NVARCHAR(MAX) = ''
SELECT @SQL = STUFF((SELECT ' UNION SELECT ''' + name 
                            + ''' AS [Column], ' 
                            + 'CAST(' + QUOTENAME(Name)
                            + ' AS NVARCHAR(MAX)) AS [ColumnValue], COUNT(*) AS [Count] FROM ' 
                            + QUOTENAME(@Table) + ' GROUP BY ' + QUOTENAME(Name)
                    FROM   sys.columns 
                    WHERE  object_id = Object_id(@Table)
                    -- concatenate result strings with FOR XML PATH
                    FOR XML PATH ('')), 1, 7, '');

EXECUTE sp_executesql @SQL;

Which will produce SQL Like the following for a table with two columns (Column1 and Column2)

SELECT 'Column1' AS [Column], 
        CAST([Column1] AS NVARCHAR(MAX)) AS [ColumnValue], 
        COUNT(*) AS [Count] 
FROM    [TableName] 
GROUP BY [Column1] 
UNION 
SELECT  'Column2' AS [Column], 
        CAST([Column2] AS NVARCHAR(MAX)) AS [ColumnValue], 
        COUNT(*) AS [Count] 
FROM    [TableName] 
GROUP BY [Column2]

---

EDIT

If you want a new result set for each column then use:

DECLARE @Table SYSNAME = 'TableName'; 
DECLARE @SQL NVARCHAR(MAX) = '';
SELECT @SQL = (SELECT ' SELECT ' + QUOTENAME(Name) 
                        + ', COUNT(*) AS [Count] FROM ' 
                        + QUOTENAME(@Table) + ' GROUP BY ' + QUOTENAME(Name) + ';'
                FROM   sys.columns 
                WHERE  object_id = Object_id(@Table)
                -- concatenate result strings with FOR XML PATH
                FOR XML PATH (''));

EXECUTE sp_executesql @SQL;

Which would produce SQL Like:

SELECT  [Column1], 
        COUNT(*) AS [Count] 
FROM    [callsupplier] 
GROUP BY [Column1];

SELECT  [Column2], 
        COUNT(*) AS [Count] 
FROM    [callsupplier] 
GROUP BY [Column2];

Answer 2

thought i would take a stab at this whilst waiting for a backup to restore

hope this does what you require

create Table #Temp 
(tableName varchar(100),
columnName varchar(100),
value varchar(1000),
distinctItems int)

Declare @tabName as varchar(100)
Declare @colName as varchar(100)
Declare @tabid as int

Declare cursorTables Cursor
for 
select t.object_id , t.name , c.name from sys.tables t inner join sys.columns c on     t.object_id = c.object_id

open cursorTables 
Fetch Next from cursorTables into 
@tabid,@tabName,@colName


while @@Fetch_Status = 0 
Begin

declare @query as nVarchar(1000)
set @query  = 'Insert into #Temp SELECT    ''' + @tabName + '''  , '''+ @colName +''', '     + @colName + ',  COUNT([' + @colName +']) AS Expr1 FROM          [' + @tabName+ '] group by     [' + @colName + ']'
print @query
exec sp_executesql @query

Fetch Next from cursorTables into 
@tabid,@tabName,@colName


End 

Close cursorTables
Deallocate cursorTables

select * from #temp

drop table #temp

produces some not very useful results on PK values and i suspect it would not work on columns greater than varchar(1000) but works on a fe of my dbs

Answer 3

This version makes a good snippet:

DECLARE @sql NVARCHAR(MAX) = N'';

SELECT @sql += 'SELECT ''' + t.name + ''', ''' + c.name + ''', ' + c.name + ', COUNT(' + c.name + ') AS C FROM ' + QUOTENAME(s.name) + '.' + QUOTENAME(t.name) + ' GROUP BY ' + c.name + ';' + CHAR(13)
    FROM sys.tables AS t
    INNER join sys.columns c on t.object_id = c.object_id
    INNER JOIN sys.schemas AS s ON t.[schema_id] = s.[schema_id] 
    WHERE s.name LIKE 'stage' AND t.name LIKE 'table' AND c.name LIKE '%whatever%';

--PRINT @sql;
EXEC sp_executesql @sql