I have 3 values :
I have three UIText
field where i can give these input and save these values into
I have a problem updating my database in a similar way....
Sql statements
<?php
// Create connection
$con=mysqli_connect("server_name","user_name","user_code","table_name");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// This SQL statement selects ALL from the table 'table.name'
$sql = "SELECT * table_name";
// Check if there are results
if ($result = mysqli_query($con, $sql))
{
// If so, then create a results array and a temporary one
// to hold the data
$resultArray = array();
$tempArray = array();
// Loop through each row in the result set
while($row = $result->fetch_object())
{
// Add each row into our results array
$tempArray = $row;
array_push($resultArray, $tempArray);
}
// Finally, encode the array to JSON and output the results
echo json_encode($resultArray);
}
$sql = "INSERT INTO table_name (column_name) VALUES('1')";
// Close connections
mysqli_close($result);
mysqli_close($con);
?>
My iOS code
for (Tickets *items in _feedItems){
if ([resultText.text isEqual:(id) items.ticketNumber]) {
status.text = @"Match found";
//Contacting database------------------------------
NSString *strURL = [NSString stringWithFormat:@"TicketDate=%@", items.ticketDate];
NSData *postData = [strURL dataUsingEncoding:NSASCIIStringEncoding
allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:@"http://webservice.com"]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-
Type"];
[request setHTTPBody:postData];
NSURLConnection *conn = [[NSURLConnection alloc]initWithRequest:request delegate:self];
if(conn)
{
NSLog(@"Connection Successful");
}
else
{
NSLog(@"Connection could not be made");
}
//Contacting database END-------------------------------------------
break;
}else {
status.text = @"Match not found";
}
}
I get a Connection Succesful from the NSLog but there is nothing getting updated in my database.
I'm trying to manually type in a ticket number with an app, and if that matches with a ticket in the database (it works), then I want the the ticketDate to change from 0 to 1.
But it does not change :/
You can use the NSURLSessionDataTask function to post data up to PHP and get a response with JSON.
- (IBAction)saveButton:(id)sender
{
NSString *noteDataString = [NSString stringWithFormat:@"name=%@&email=%@", nameTextField.text, emailTextField.text];
NSURLSessionConfiguration *defaultConfigObject = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *defaultSession = [NSURLSession sessionWithConfiguration: defaultConfigObject delegate: nil delegateQueue: [NSOperationQueue mainQueue]];
NSURL * url = [NSURL URLWithString:@"http://mydomain.com/iOS/Tulon/phpFile.php"];
NSMutableURLRequest * urlRequest = [NSMutableURLRequest requestWithURL:url];
[urlRequest setHTTPMethod:@"POST"];
[urlRequest setHTTPBody:[noteDataString dataUsingEncoding:NSUTF8StringEncoding]];
NSURLSessionDataTask * dataTask =[defaultSession dataTaskWithRequest:urlRequest completionHandler:^(NSData *dataRaw, NSURLResponse *header, NSError *error) {
NSDictionary *json = [NSJSONSerialization
JSONObjectWithData:dataRaw
options:kNilOptions error:&error];
NSString *status = json[@"status"];
if([status isEqual:@"1"]){
//Success
} else {
//Error
}
}];
[dataTask resume];
}
and you can handle the response in PHP with this code:
<?php
if (isset ($_POST["name"]) && isset ($_POST["email"])){
$name = $_POST["name"];
$email = $_POST["email"];
} else {
$name = "Tulon";
$email = "tulon@yahoo.com";
}
// Insert value into DB
$sql = "INSERT INTO $dbtable (name, email) VALUES ('$name', '$email');";
$res = mysql_query($sql,$conn) or die(mysql_error());
mysql_close($conn);
if($res) {
$response = array('status' => '1');
} else {
die("Query failed");
}
echo json_encode($res);
exit();
?>
Hope this helps
Can you try this? may be it works for you.
NSString *strURL = [NSString stringWithFormat:@"name=%@&email=%@", nameTextField.text, emailTextField.text];
NSData *postData = [strURL dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:@"http://mydomain.com/iOS/Tulon/phpFile.php"]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"];
[request setHTTPBody:postData];
NSURLConnection *conn = [[NSURLConnection alloc]initWithRequest:request delegate:self];
if(conn)
{
NSLog(@"Connection Successful");
}
else
{
NSLog(@"Connection could not be made");
}
After this implement following methods to get response
- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData*)d
{
[self.ask_data appendData:d];
}
- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error
{
}
- (void)connectionDidFinishLoading:(NSURLConnection *)connection
{
NSString *responseText = [[NSString alloc] initWithData:self.ask_data encoding:NSUTF8StringEncoding];
NSLog(@"response=%@",responseText);
}