Exporting jars with resources

Question

I\'m trying to build a large Java project by building many small, modular projects. I want each small project to be entirely self contained, holding all of its resources (su

Answer 1

To add another source folder for your resources first create the folder. In a java perspective, select the project and from the context menu choose "configure build path". In the source folder tab you can make that newly created folder a source folder for your project. From then on, all resources under that folder can be exported to a jar with the project classes.

By the way, the path you specify for getResourceAsStream is either just the resource file name if the resource is in the same package as the class or is the relative path name (starting with a slash) for the resource from the source folder you're using.

Answer 2

You have multiple projects comprising a single application? So if you run this via Eclipse all works?
If yes, then just in your main project do Export as Runnable Jar. This should work as well

Answer 3

This solution worked for me:

/**
 *
 * @author David
 */
public class JavaApplication60 {
/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
    //http://img.viralpatel.net/java-cup-logo.png

    //located in a package not in the current one
    URL url = new JavaApplication60().getResource("/javaapplication60/newpackage/java-cup-logo.png");
    System.out.println(url.getPath());
    //located in same package
    url = new JavaApplication60().getResource("/javaapplication60/java-cup-logo.png");
    System.out.println(url.getPath());
}

public InputStream getResourceAsStream(String name) {
    name = resolveName(name, this.getClass());
    ClassLoader cl = getClass().getClassLoader();
    if (cl == null) {
        return ClassLoader.getSystemResourceAsStream(name); // A system class.
    }
    return cl.getResourceAsStream(name);
}

public java.net.URL getResource(String name) {
    name = resolveName(name, this.getClass());
    ClassLoader cl = getClass().getClassLoader();
    if (cl == null) {
        return ClassLoader.getSystemResource(name);  // A system class.
    }
    return cl.getResource(name);
}


/*
 * The resolveName method adds a package name prefix if the name is not
 * absolute, and removes any leading "/" if the name is absolute. It is
 * possible, though uncommon, to have classes in diffent packages sharing
 * the same resource.
 */
private String resolveName(String name, Object clazz) {
    if (name == null) {
        return name;
    }
    if (!name.startsWith("/")) {
        Class c = clazz.getClass();
        while (c.isArray()) {
            c = c.getComponentType();
        }
        String baseName = c.getName();
        int index = baseName.lastIndexOf('.');
        if (index != -1) {
            name = baseName.substring(0, index).replace('.', '/') + "/" + name;
        }
    } else {
        name = name.substring(1);
    }
    return name;
}
}

My package structure looked like this:

References:

• Location-Independent Access to Resources