Hive sort array column with respect to other array column in same table

Question

I have a table in hive , with 2 columns as col1 array and col2 array. Output is as shown below

col1                


        

Answer 1

Explode both arrays, sort, then aggregate arrays again. Use sort in the subquery before collect_list to sort the array:

with your_data as(
select array(1,2,3,4,5) as col1,array(0.43,0.01,0.45,0.22,0.001)as col2
)

select original_col1,original_col2, collect_list(c1_x) as new_col1, collect_list(c2_x) as new_col2
from
(
select d.col1 as original_col1,d.col2 as original_col2, c1.x as c1_x, c2.x as c2_x, c1.i as c1_i  
 from your_data d
      lateral view posexplode(col1) c1 as i,x
      lateral view posexplode(col2) c2 as i,x
where c1.i=c2.i 
distribute by original_col1,original_col2
sort by c2_x
)s
group by original_col1,original_col2;

Result:

OK
original_col1   original_col2                   new_col1        new_col2
[1,2,3,4,5]     [0.43,0.01,0.45,0.22,0.001]     [5,2,4,1,3]     [0.001,0.01,0.22,0.43,0.45]
Time taken: 34.642 seconds, Fetched: 1 row(s)

Edit: Simplified version of the same script, you can do without second posexplode, use direct reference by position d.col2[c1.i] as c2_x

with your_data as(
select array(1,2,3,4,5) as col1,array(0.43,0.01,0.45,0.22,0.001)as col2
)

select original_col1,original_col2, collect_list(c1_x) as new_col1, collect_list(c2_x) as new_col2
from
(
select d.col1 as original_col1,d.col2 as original_col2, c1.x as c1_x, d.col2[c1.i] as c2_x, c1.i as c1_i  
 from your_data d
      lateral view posexplode(col1) c1 as i,x
distribute by original_col1,original_col2
sort by c2_x
)s
group by original_col1,original_col2;