What is the best way to optimize schema for capturing attendance data

Question

We have a sports training camp which is regularly attended by various teams in the city. We have a session per day spanning 2 hrs(9-11 AM) and the time slots could vary for

Answer 1

AttMst
  id | date

AttDet
  attdetid | id | userid

In this way you need to store day in AttMst and the present users on that day will be stored in AttDet.

Answer 2

IMHO, having a single row per user per month with a lot of concatenated characters isn't going to be any better than having lots of rows with a single character on it, especially if you're going to have to split that string everytime you want to display the data on another application.

If you just want to figure out the number of days a user attended your camp, why not create a table specifically for that? Everytime you logged a user's attendance, you would only have to update that table by increasing the number of days that the user had attended. As such, this value would not be calculated on-the-fly and it shouldn't give you any performance issues.

So, my advice would consist in two tables:

id | user_id | date | present

and

user_id | month | attendance

You should have some indexes on the user_id field as well, in order to increase the performance of the system.

Cheers

Answer 3

You use the word "optimize" in the question title without explaining what it is you want to optimize.

If you're talking about query performance then you do not have a problem. The number of records you can have is governed by the number of sessions you have each day (because only one team can attend any given session). If you run ten sessions a day that's three hundred records per month. If you run one hundred sessions a day that is three thousand records a month. These are not big volumes of data. So you are making a bad decision by skewing your database design to avoid a performance problem which isn't there.

You mentioned spreadsheets in one of your comments. That is not a bad design to have. Along the top row there are sessions, down the side there are teams, and the cells show whether a team was present at a session. Those map to three database tables: SESSIONS, TEAMS and the intersection table TEAM_SESSIONS. You only need a record in TEAM_SESSIONS when a team attended a session.

As a proof of concept I knocked up three tables in Oracle.

SQL> desc teams
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 ID                                        NOT NULL NUMBER
 NAME                                               VARCHAR2(20 CHAR)

SQL> desc sessions
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 ID                                        NOT NULL NUMBER
 SSN_DAY                                            DATE
 SSN_START                                          NUMBER(4,2)
 SSN_END                                            NUMBER(4,2)

SQL> desc team_sessions
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 TEAM_ID                                   NOT NULL NUMBER
 SESSION_ID                                NOT NULL NUMBER

SQL>

The PIVOT function introduced in Oracle 11g makes it a cinch to knock up a matrix (different flavours of DBMS will have different ways to approach this). As you can see, three teams have booked sessions today, nobody wants to train at lunchtime, and Bec United are keen as mustard (or need the training)!

SQL> select * from (
  2      select t.name as team_name
  3             , trim(to_char(s.ssn_start))||'-'||trim(to_char(s.ssn_end)) as ssn
  4             , case when ts.team_id is not null then 1 else 0 end as present
  5      from   sessions s
  6             cross join teams t
  7             left outer join team_sessions ts
  8                  on (ts.team_id = t.id
  9                      and ts.session_id = s.id )
 10      where s.ssn_day = trunc(sysdate)
 11      )
 12  pivot
 13      ( sum (present)
 14        for ssn in ( '9-11', '11-13', '13-15', '15-17', '17-19')
 15      )
 16  order by team_name
 17  /

TEAM_NAME                '9-11'    '11-13'    '13-15'    '15-17'    '17-19'
-------------------- ---------- ---------- ---------- ---------- ----------
Balham Blazers                0          1          0          0          0
Bec United                    1          0          0          0          1
Dinamo Tooting                0          0          0          0          0
Melchester Rovers             0          0          0          1          0

SQL>

Anyway, the virtue of this data model is that it is flexible. We can count how often a team attends, what times they attend, what day of the week they attend, what sessions are always booked, what sessions are rarely booked, etc. Plus it is easy to manage the data. In particular, the advantage of the three table solution over just two tables is that it is easier to prevent double bookings and non-standard or overlapping time slots.

You see, normalisation isn't just some moon language we use to bamboozle the innocent, it offers real practical benefits. There are few scenarios where driving down to at least BCNF is not the best idea.

Answer 4

You should ask yourself why you would do that.

There are some possibilities, but it is likely that your database schema won't be fully normalized.

So first of all: what do you want to achieve and what are the reasons for that?

Some possibilities:

• Some DBMS provide the ability to create a user-defined type
• You could use a bitwise approach (in mysql the easiest way for this is using the SET datatype)

But again: what is your current problem, since finding out the number of days someone was present is nothing more than joining the appropriate tables, and aggregate with a count function