Jquery check if array contains duplicate string

Question

How to check if array contains a duplicate string , i have validateArray = [\'sa\',\'sa\',\'yu\'] i have used the following function from SO but same not working for me.

Answer 1

This is working for me:

var reportRecipients = ['AAA', 'XYZ', 'AAA', 'ABC', 'XXX', 'XYZ', 'PQR'];
var recipientsArray = reportRecipients.sort(); 

var reportRecipientsDuplicate = [];
for (var i = 0; i < recipientsArray.length - 1; i++) {
    if (recipientsArray[i + 1] == recipientsArray[i]) {
        reportRecipientsDuplicate.push(recipientsArray[i]);
    }
}

Hope that helps.

Answer 2

Please try this, if the sort function is not working well :

    var all_list= ['sa','sa','yu'] 
    var duplicates_list = [];
    var unique_list = [];
    $.each(all_list, function(key, value){
            if($.inArray(value, unique_list ) == -1){
                unique_list.push(value);
            }else{
                if($.inArray(value, duplicates_list ) == -1){
                    duplicates_list.push(value);
                }
            }
    });

//duplicated elements 
console.log(duplicates_list )

Answer 3

Take a look at this:

function getDistinctArray(arr) {
    var compareArray = new Array();
    if (arr.length > 1) {
        for (i = 0;i < arr.length;i++) {
            if (compareArray.indexOf(arr[i]) == -1) {
                compareArray.push(arr[i]);
            }
        }
    }
    return compareArray;
}

And here is a working fiddle

Answer 4

just use unique() method.

$.unique(reportRecipients);

https://api.jquery.com/jQuery.unique/