Why do I get an error that “Sync is not satisfied” when moving self, which contains an Arc, into a new thread?

后端 未结 1 657
南方客
南方客 2021-01-14 10:10

I have a struct which holds an Arc> and I\'m trying to add a method which takes ownership of self, and moves the ownershi

相关标签:
1条回答
  • 2021-01-14 10:47

    How does this work?

    Let's check the requirements of thread::spawn again:

    pub fn spawn<F, T>(f: F) -> JoinHandle<T> 
    where
        F: FnOnce() -> T,
        F: Send + 'static,   // <-- this line is important for us
        T: Send + 'static, 
    

    Since Foo contains an Arc<Receiver<_>>, let's check if and how Arc implements Send:

    impl<T> Send for Arc<T> 
    where
        T: Send + Sync + ?Sized,
    

    So Arc<T> implements Send if T implements Send and Sync. And while Receiver implements Send, it does not implement Sync.

    So why does Arc have such strong requirements for T? T also has to implement Send because Arc can act like a container; if you could just hide something that doesn't implement Send in an Arc, send it to another thread and unpack it there... bad things would happen. The interesting part is to see why T also has to implement Sync, which is apparently also the part you are struggling with:

    The error doesn't make sense to me as I'm not trying to share it between threads (I'm moving it, not cloning it).

    The compiler can't know that the Arc in Foo is in fact not shared. Consider if you would add a #[derive(Clone)] to Foo later (which is possible without a problem):

    fn main() {
        let (example, sender) = Foo::new();
        let clone = example.clone();
        let handle = example.run_thread();
        clone.run();
        // oopsie, now the same `Receiver` is used from two threads!
    
        handle.join();
    }
    

    In the example above there is only one Receiver which is shared between threads. And this is no good, since Receiver does not implement Sync!

    To me this code raises the question: why the Arc in the first place? As you noticed, without the Arc, it works without a problem: you clearly state that Foo is the only owner of the Receiver. And if you are "not trying to share [the Receiver]" anyway, there is no point in having multiple owners.

    0 讨论(0)
提交回复
热议问题