I have a csv file and am trying to get one specific value on, say, line 20, column 3.
But so far, all I managed is to display all values on column 3 (here c
if you only know the column number and the line number you can do like this:
TheRow = 2 # Note that row 1 is the header row
TheColumn = 2 # first column == 0
for row in d:
if d.line_num == TheRow:
print("row %s: %s" % (str(d.line_num), str(row) ) )
print( row[d.fieldnames[TheColumn]] )
output:
row 2: {'t1': '12', 't2': '23', 't3': '31'}
31
Naive solution:
target_row = 5
for num, line in enumerate(d):
if num == target_row:
print line["name"]
break
I removed the intermediate variable score
.
Note that this is non-optimal, as you iterate until you reach the desired row, but I don't know if there is random access to lines in the DictReader.
In short, convert the output of csv.DictReader to a list format and access the values with index.
Note: The value returned when you access by index will be an object with keys corresponding to the column names in the CSV file
Use Case:
I had a similar need. I only wanted to read a subset of rows, say lines 10-15 from a total of 100 lines.
A simple solution that worked was to convert it into list:
# Observe that I am converting the output of DictReader into a list format
lines = list(csv.DictReader(open('somefile.csv', 'r')))
# Once I have the list of objects, I can simple access it with range
for i in range(10, 15):
line = lines[i]
# If you want to read the value of a specific column
print line['column_name']
Hope this helps.
Skipping ahead to the desired line, just as in the other answer, but with slicing on the CSV-reading iterator instead of a manual loop:
import csv, itertools
rownum = 20
colname = "name"
line = itertools.islice(d, rownum - 1, rownum).next()
score = line[colname]
(Not the most beautiful code, I know, but that's just to illustrate the point.)