javascript array.splice() does not remove element in the array?

Question

I have a remove[] array which has all the index positions of all the element with 0 in the data array (as below).

data array:

Retail,1,Utilities,1,Fo         


        

Answer 1

If you look at your original array and the first result array, you'll notice that non-0 elements ARE being removed. The problem from what I can tell is that your array remove is looking for indices that have since been shifted over one to the left upon the removal of previous ones. You will need to add a correcting adjustment for this in your final for loop, or approach this another way.

Answer 2

I think you can do it pretty fast this way:

var dataArr = ["Retail",1,"Utilities",1,"Food & Restaurant",3,"No Data",4,"Construction",0,"Non-profit",1,"Financial Services",12,"Technology",2,"Law",3,"Religion",3,"Retired",2,"Insurance",0,"Real Estate",2,"Audit",3,"Business Organizations",3,"Media & Marketing",0,"Education",3,"Transportation",0,"Manufacturing",0,"Entertainment & Sports",0,"Architecture & Engineering",0,"Cultural Institutions",0,"Government",0,"Banking",0,"Health Care",0,"Business Services",0];

var item = 0; // value of the item to remove

while (dataArr.indexOf(item) > -1) {
 dataArr.splice(dataArr.indexOf(item), 1);
}

console.log(dataArr);

Answer 3

I use a library called DevBox.Linq.JS

It basically adds Linq type functionality to Javascript Arrays. For example, it adds "Remove":

   Array.prototype.Remove = function (condition) {
    if (condition == undefined) {
        console.error('Informe a expressão para executar a tarefa.')
        return;
    }

    for (var i = 0 ; i < this.length ; i++) {
        if (condition(this[i]))
            this.splice(i, 1);
    }
}

This way you can use it with a lambda like this:

myArray.remove(i=>i=="valueToDelete");

Hope it helps, It already has all the functionality so you don't have to deal with that pesky splice.

Answer 4

Every time you remove one, you're making any further cached indices obsolete because the array from that point forward is reindexed.

As a result, you're removing the wrong items after the first.

You should iterate the remove array in reverse instead.

var i = remove.length;
while (i--) {
    if (remove[i] != undefined)
        options.series[0].data.splice(remove[i],1);
}   

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Additionally, you can improve the performance and get rid of the undefined test if you simply .push() each index into the remove array...

remove.push(index);

Answer 5

If you want to remove all the elements from an array, it's better don't use splice but length:

options.series[0].data.length = 0;

See: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/length

Update:

I misunderstood the question. In your case I will probably filter out the elements that are zero, instead of makes two loop (one for collect them, and one for remove them). So, something like:

function isNotZero(item) {return item[1] !== 0}

var filtered = options.series[0].data.filter(isNotZero);

options.series[0].data = filtered;

See: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/filter

If the browser you want to support doesn't implement ES5, I will suggest to you to use a shim for all the es5 methods (in that page there is one for filter), or library like underscore

Answer 6

My problem was that splice was removing the wrong element from the array. I saw the answer with the while loop but the solution that I made is :

var index = jQuery.inArray(element, arr);
arr.splice(index,1);