Python two lists finding index value

Question

listEx = [\'cat *(select: \"Brown\")*\', \'dog\', \'turtle\', \'apple\']
listEx2 = [\'hampter\',\' bird\', \'monkey\', \'banana\', \'cat\']

for j in listEx2:
    fo         


        

Answer 1

Just use enumerate:

listEx = ['cat *(select: "Brown")*', 'dog', 'turtle', 'apple']
listEx2 = ['hampter',' bird', 'monkey', 'banana', 'cat']

for j in listEx2:
    for pos, i in enumerate(listEx):
        if j in i:
            print j, "found in", i, "at position", pos, "of listEx"

This will print

cat found in cat *(select: "Brown")* at position 0 of listEx

Answer 2

Your problem is that you wrote j instead of i in the last line:

for j in listEx2:
    for i in listEx:
        if j in i:
            print listEx.index(i)
#                              ^ here

However, a better approach is to use enumerate:

for item2 in listEx2:
    for i, item in enumerate(listEx):
        if item2 in item:
            print i