How can I start a for-loop with 01 instead of 1?

Question

How do I start a for-loop with 01 as opposed to 1? I\'ve tried the below, but it doesn\'t seem to work.

for ($i = 01; $i <= 12;          


        

Answer 1

01 is the octal number 1 (which is equivalent to the decimal 1 in this case). Since you want to format the output to have two digits for the number, consider using printf:

printf("<option value='%02d'", $i);

• % marks the start of a conversion
• 0 means "pad the string with zero"
• 2 means "the replacement should have a minimum length of 2"
• d means "the argument is an integer"

References:

• PHP Manual: printf
• PHP Manual: sprintf

Answer 2

PHP will parse 01 as an integer, so it will become 1. You can't iterate on a string like '01' so you'll have to edit the value of $i later on in your code.

If you need a 01 later on, you could use padding. http://php.net/manual/en/function.str-pad.php

Answer 3

You can't really start an integer at 01, you will need to pad the value, probably using str_pad to prefix leading elements to a string:

$value = $i;
if ($i < 10) {
    $value = str_pad($i, 2, "0", STR_PAD_LEFT);
}

Note that for different unit types you will obviously need to alter the desired pad_length.

Answer 4

for ($i = 01; $i <= 12; $i++) {

            $value = strlen($i);
            if($value==1){
                $k = "0".$i;
            }else
            {
                $k=$i;
            }
            echo "<option value='$k'";
            if ($i == $post_response[expiremm]) {
                echo " selected='selected'";
            }
            $month_text = date("F", mktime(0, 0, 0, $i + 1, 0, 0, 0));
            echo ">$month_text</option>";
        }

For loop can not start with 01 so you can do like this as shown above

Answer 5

for ($i = 1; $i <= 25; $i++) {
echo str_pad($i, 2, "0", STR_PAD_LEFT);
echo "<br/>"; }

it may help you..