int num = new int(); What happens when this line executes?

Question

Got to know a new thing today that we can create integers by using new operator as below

int num = new int();

Now I wonder if

Answer 1

I think, you are looking for

int num = default(int);

This is also useful when facing compilation error, Unassigned local variable

Answer 2

int i = new int();

is equavalent to

int i = 0;

There is no difference between them. They will generate the same IL code at all.

  // Code size       4 (0x4)
  .maxstack  1
  .locals init ([0] int32 num)
  IL_0000:  nop
  IL_0001:  ldc.i4.0
  IL_0002:  stloc.0
  IL_0003:  ret

From Using Constructors (C# Programming Guide)

Constructors for struct types resemble class constructors, but structs cannot contain an explicit default constructor because one is provided automatically by the compiler. This constructor initializes each field in the struct to the default values.

Default value of integers is 0. Check for more Default Values Table

Answer 3

The answer is in section 4.1.2 of the C# language spec:

All value types implicitly declare a public parameterless instance constructor called the default constructor. The default constructor returns a zero-initialized instance known as the default value for the value type:

Like any other instance constructor, the default constructor of a value type is invoked using the new operator. For efficiency reasons, this requirement is not intended to actually have the implementation generate a constructor call. In the example below, variables i and j are both initialized to zero.

class A
{
    void F() {
        int i = 0;
        int j = new int();
    }
}

In terms of doing things without using a default constructor, such as

int x = 1;

That's covered by section 4.1.4 of the C# Language Spec:

Most simple types permit values to be created by writing literals (§2.4.4). For example, 123 is a literal of type int