Why do I lose the remainder of a value after performing arithmetic in C?

Question

I am trying to learn basic C programming by following a textbook and I must be missing something about either the data types, rounding, and/or order of operations because wh

Answer 1

Integer division: the integer value after dividing two ints gets stored in a floating point format. Eg:

 float a = 3/5;

here an integer division will occur between 3 and 5 resulting in 0. Now, if you try to store this 0 in a float variable, it will be stored as 0.00.

    min = sec/secpermin;

Should be

    min = (float)sec/secpermin;

or

    min = sec/(float)secpermin;

or, as @alk pointed out, you could also do this instead:

    min = sec;     
    min /= secpermin;    // min=min/secpermin;   here, typecasting is not required as 
                        // numerator (min) is already float.

Alternatively, you can make them all float, and while printing typecast them as int.