I can\'t render a view to a string and then redirect, despite this answer from Feb (after version 1.0, I think) that claims it\'s possible. I thought I was doing something w
public Action SendEmail(int id)
{
//Let's say that id is the db id of an order that a customer has just placed.
//Go get that model from the db.
MyModel model = new Model(id);
//Now send that email. Don't forget the model and controller context.
SendEmail(model, this.ControllerContext);
//Render (or redirect!)
return RedirectToAction("Wherever");
}
private static void SendEmail(MyModel model, ControllerContext controllerContext)
{
//Recreate the viewdata
ViewDataDictionary viewData = controllerContext.Controller.ViewData;
viewData["Order"] = model;
string renderedView = "";
CustomRenderers customRenderers = new CustomRenderers();
//Now render the view to string
//ControllerContext, ViewPath, MasterPath, ViewDataDictionary, TempDataDictionary
//As you can see, we're not passing a master page, and the tempdata is in this instance.
renderedView = RenderViewToString(controllerContext, "~/Views/Orders/Email.aspx", "", viewData, null);
//Now send your email with the string as the body.
//Not writing that, as the purpose is just to show the rendering. :)
}
//Elsewhere...
public class CustomRenderers
{
public virtual string RenderViewToString(ControllerContext controllerContext, string viewPath, string masterPath, ViewDataDictionary viewData, TempDataDictionary tempData)
{
if (tempData == null)
{
tempData = new TempDataDictionary();
}
Stream filter = null;
ViewPage viewPage = new ViewPage();
//Right, create our view
viewPage.ViewContext = new ViewContext(controllerContext, new WebFormView(viewPath, masterPath), viewData, tempData);
//Get the response context, flush it and get the response filter.
var response = viewPage.ViewContext.HttpContext.Response;
response.Flush();
var oldFilter = response.Filter;
try
{
//Put a new filter into the response
filter = new MemoryStream();
response.Filter = filter;
//Now render the view into the memorystream and flush the response
viewPage.ViewContext.View.Render(viewPage.ViewContext, viewPage.ViewContext.HttpContext.Response.Output);
response.Flush();
//Now read the rendered view.
filter.Position = 0;
var reader = new StreamReader(filter, response.ContentEncoding);
return reader.ReadToEnd();
}
finally
{
//Clean up.
if (filter != null)
{
filter.Dispose();
}
//Now replace the response filter
response.Filter = oldFilter;
}
}
}
In your Orders/Email.aspx view, make sure you refer to everything from the ViewData, rather than the model. you can do this:
<% MyModel model = (MyModel)ViewData["Order"] %>
Updated.
Now that I understand that you want to use the view engine to generate the actual email in html, I propose the following:
Code to render action to text within a controller: http://mikehadlow.blogspot.com/2008/06/mvc-framework-capturing-output-of-view_05.html
Minor edits to your code:
public ActionResult Certifications(string email_intro)
{
//a lot of stuff
ViewData["users"] = users;
if (isPost())
{
//create the viewmodel
var view_model = new ViewModels.Emails.Certifications.Open(userContext) { emailIntro = email_intro };
foreach (var user in users)
{
if (user.Email_Address.IsValidEmailAddress())
{
view_model.user = user;
view_model.certification302Summary.subProcessesOwner = new SubProcess_Certifications(RecordUpdating.Role.Owner, null, null, user.User_ID, repository);
SendEmail(view_model);
}
}
return RedirectToAction("Certifications");
}
return View();
}
public void SendEmail(ViewModels.Emails.Certifications.Open model)
{
var vd = context.Controller.ViewData;
vd["model"] = model;
var renderer = new CustomRenderers();
// Implement the actual email rendering as a regular action method on this controller
var text = this.CaptureActionHtml(c => (ViewResult)c.RenderEmail(model));
var a = text;
}
Here is an alternative method for rendering a view to a string that never results in data being output to the response (therefore it should avoid your problem): http://craftycodeblog.com/2010/05/15/asp-net-mvc-render-partial-view-to-string/
To render a regular view instead of a partial view, you'll need to change "ViewEngines.Engines.FindPartialView" to "ViewEngines.Engines.FindView".