I have the following XML:
0
1
06098INF17613
XmlText
expects a text node, but what you have are actually element nodes. I don't know if there's a direct way to do that, but you can have a XmlAnyElement
node to collect the result of the deserialization, and afterwards you merge them in a single string if that's what you need, as shown in the example below.
[XmlRoot("Plan")]
public class EPlan
{
[XmlElement("Error")]
public string Error { get; set; }
[XmlElement("Description")]
public string Description { get; set; }
[XmlElement("Document")]
public List<EDocument> Documents { get; set; }
}
[XmlType]
public class EDocument
{
private string document;
[XmlAnyElement]
[EditorBrowsable(EditorBrowsableState.Never)]
public XmlElement[] DocumentNodes { get; set; }
[XmlIgnore]
public string Document
{
get
{
if (this.document == null)
{
StringBuilder sb = new StringBuilder();
foreach (var node in this.DocumentNodes)
{
sb.Append(node.OuterXml);
}
this.document = sb.ToString();
}
return this.document;
}
}
}
static void Test()
{
string xml = @"<Plan>
<Error>0</Error>
<Description>1</Description>
<Document>
<ObjectID>06098INF1761320</ObjectID>
<ced>109340336</ced>
<abstract>DAVID STEVENSON</abstract>
<ced_a />
<NAM_REC />
<ced_ap2 />
</Document>
<Document>
<ObjectID>id2</ObjectID>
<ced>ced2</ced>
<abstract>abstract2</abstract>
<ced_a />
<NAM_REC />
<ced_ap2 />
</Document>
</Plan>";
XmlSerializer xs = new XmlSerializer(typeof(EPlan));
MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(xml));
EPlan obj = xs.Deserialize(ms) as EPlan;
Console.WriteLine(obj.Documents[0].Document);
}