I am trying to filter some objects in my attempt to understand JS better and I\'m using underscore.js
I come from a C# background and am used to LINQ however undersc
A more concise way to accomplish this would be with underscore's chain() function:
var noMushrooms = _(products).chain()
.filter(function (x) {
return !x.containsNuts;})
.reject(function(x){
return _(x.ingredients).any(function(y){
return y === "mushrooms";
});
})
.value();
You just need to remove the !
from the reject
callback so that it look like this:
var noMushrooms = _(noNuts).reject(function(x){
return _(x.ingredients).any(function(y){return y === "mushrooms";});
});
Otherwise you're rejecting the ones that don't contain mushrooms instead of those that do.
This will give the desired result
var no_nuts = _.filter(products,function(item) {
return !item.containsNuts;
});
var no_mushroom = _.reject(no_nuts,function(item) {
return _.any(item.ingredients,function(item1) {
return item1 === "mushrooms"
});
});
console.log(no_mushroom);
reject()
does the opposite of filter()
, and any()
is equivalent to some method of arrays which returns true when any of the element in the array when passed through a callback returns true.
I managed to get my solution all wrapped up into one filter call so thought I'd post it:
products = [
{ name: "Sonoma", ingredients: ["artichoke", "sundried tomatoes", "mushrooms"], containsNuts: false },
{ name: "Pizza Primavera", ingredients: ["roma", "sundried tomatoes", "goats cheese", "rosemary"], containsNuts: false },
{ name: "South Of The Border", ingredients: ["black beans", "jalapenos", "mushrooms"], containsNuts: false },
{ name: "Blue Moon", ingredients: ["blue cheese", "garlic", "walnuts"], containsNuts: true },
{ name: "Taste Of Athens", ingredients: ["spinach", "kalamata olives", "sesame seeds"], containsNuts: true }
];
it("given I'm allergic to nuts and hate mushrooms, it should find a pizza I can eat (functional)", function () {
var productsICanEat = [];
productsICanEat = _(products).filter(function (x) { return !x.containsNuts && !_(x.ingredients).any(function(y){return y === "mushrooms";});});
expect(productsICanEat.length).toBe(1);
});