I need to generate a vector of the following format using R:
1:10, 1:10, 11:20, 11:20, ... 121:130, 121:130
Is there an easier way than cre
Is this what you want?
unlist(lapply(rep(seq(1, 121, by=10), each=2), function(x) seq(x, x+9)))
Another way:
x <- matrix(1:130, 10, 13)
c(rbind(x, x))
Possible more efficient version:
x <- 1:130
dim(x) <- c(10,13)
c(rbind(x, x))
Alternatively, you could use a combination of rep
and outer
, such as:
c(outer(1:10,rep(0:12,each=2),function(x,y)10*y+x))
I think this will do you.
x <- ((0:12)*10)+1
y <- x + 9
repeatVectors <- function(x,y){
rep(seq(x,y),2)
}
z <- mapply(repeatVectors, x,y)
z <- as.vector(z)
Also you could do:
rep(1:10, 26) + rep(seq(0,120,10), each=20)
A method using split
is
unlist(rep(split(seq_len(130), rep(1:13, each=10)), each=2), use.names=FALSE)