PHP - PDO fetch resultset with column as index and column as value [duplicate]

Answer 1

I think it can be done with fetch options.

$sth = $dbh->prepare("SELECT date, price FROM some_table");
$sth->execute();


$sth->fetchAll(PDO::FETCH_KEY_PAIR);

It only works if the fetched data are a pair of values.

Answer 2

I don't think there's anything built-in that will do that. You can do it by using a normal fetch() loop:

$results = array();
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
    $results[$row['date']] = $row['price'];
}

Answer 3

Try foreach ($sql_stmt as $row)... Its easy to handle all your result sets...

Change the database name , user id , table name etc., according to your system

$dsn = 'mysql:dbname=testdb;host=127.0.0.1';
$user = 'dbuser';
$password = 'dbpass';

try {
    $dbConnection= new PDO($dsn, $user, $password);
} catch (PDOException $e) {
    echo 'Connection failed: ' . $e->getMessage();
}

$dbConnection->setAttribute(PDO::ATTR_EMULATE_PREPARES, TRUE);

$sql_stmt = $dbConnection->prepare($sql_query="select date,price from table;");

$sql_stmt->execute();
foreach ($sql_stmt as $row) {
$date_col=$row['date']; 
$price_col=$row['price']; 
print $date_col;
print $price_col;
}

If you want to store value in array then use, like below in same foreach loop (declare and increment $i)

$date_col[$i]=$row['date']; 
$price_col[$i]=$row['price'];