sum some xml nodes values in sql server 2008

Question

Please consider this XML:

    10 
    20 
    

        

Answer 1

select @xml.value('sum(/Parent[@ID = "p"]/Child)', 'float') as Sum

The use of float protects against there being no Parent with that ID. You can then cast this result to int.

Answer 2

Try this one -

DECLARE @XML XML
SELECT @XML = '
<Parent ID="p">
    <Child ID="1">10</Child > 
    <Child ID="2">20</Child > 
    <Child ID="3">0</Child > 
</Parent >
<Parent ID="p2">
    <Child ID="1">15</Child > 
    <Child ID="2">20</Child > 
    <Child ID="3">5</Child > 
</Parent >'

SELECT 
      value = SUM(t.value)
    , t.id 
FROM (
    SELECT 
          value = p.value('.', 'INT')
        , id = p.value('./../@ID', 'VARCHAR(50)')
    FROM @XML.nodes('/Parent/Child') t(p)
) t
--WHERE t.id = 'p'
GROUP BY t.id

Answer 3

Try this :-

 Declare @xml xml 
set @xml='<Parent ID="p">
         <Child ID="1">10</Child > 
         <Child ID="2">20</Child > 
         <Child ID="3">0</Child > 
          </Parent >'

 Select @xml.value('sum(/Parent/Child)','int') as Sum

Result : 30

or if you want the sum for a specific Parent ID then try the below query

 Select @xml.value('sum(/Parent/Child)','int') AS SumVal
 where @xml.exist('/Parent[@ID="p"]') = 1;

Demo in SQL FIDDLE

Answer 4

Try this :

DECLARE @SearchKeyWords XML 

SET @SearchKeyWords =
'<Parent ID=''p''>
    <Child ID="1">10</Child > 
    <Child ID="2">20</Child > 
    <Child ID="3">0</Child > 
</Parent >' 

DECLARE @TempSearchKeyWords TABLE
        (
            SearchKeyWord INT
        )

INSERT INTO @TempSearchKeyWords                     
SELECT SearchKeyWords.SearchKeyword.value('.',' int ') AS SearchKeyword             
FROM @SearchKeyWords.nodes('/Parent/Child') AS SearchKeyWords(SearchKeyword)

SELECT SUM(SearchKeyWord) FROM @TempSearchKeyWords

This will return 30.