PDO - passing a field name as a variable

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粉色の甜心
粉色の甜心 2021-01-13 17:39

I\'m just migrating my code from mysql_query style commands to PDO style and I ran into a problem. THe old code looked like this :

$query_list_menu = \"SELE         


        
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  • 2021-01-13 18:11

    If $_GET['section_name'] contains a column name, your query should be:

    $query_list_menu = "SELECT " . $_GET['section_name'] . " from myl_menu_hide_show WHERE id=:id";
    

    Giving:

    $query_list_menu = "SELECT :section_name from myl_menu_hide_show WHERE id=:id";
    $result_list_menu = $db->prepare($query_list_menu);
    $result_list_menu->bindValue(':id', $_GET['id'] , PDO::PARAM_INT);  
    $result_list_menu->execute();
    

    The reason is that you want the actual name of the column to be in the query - you'd changed it to be a parameter, which doesn't really make much sense.

    I'll also add that using $_GET['section_name'] directly like this is a massive security risk as it allows for SQL injection. I suggest that you validate the value of $_GET['section_name'] by checking it against a list of columns before building and executing the query.

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  • 2021-01-13 18:29

    There is no good and safe way to select just one field from the record based on the user's choice. The most sensible solution would be to select the whole row and then return the only field requested

    $sql = "SELECT * from myl_menu_hide_show WHERE id=?";
    $stmt = $db->prepare($query_list_menu);
    $stmt->execute([$_GET['id']]);
    $row = $stmt->fetch();
    return $row[$_GET['section_name']] ?? false;
    
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