Python gzip folder structure when zipping single file

Question

I\'m using Python\'s gzip module to gzip content for a single file, using code similar to the example in the docs:

import gzip
content = \"Lots of content he         


        

Answer 1

You must use gzip.GzipFile and supply a fileobj. If you do that, you can specify an arbitrary filename for the header of the gz file.

Answer 2

Why not just open the file without specifying a directory hierarchy (just do gzip.open("file.txt.gz"))?. Seems to me like that works. You can always copy the file to another location, if you need to.

Answer 3

If you set your current working directory to your output folder, you can then call gzip.open("file.txt.gz") and the gz file will be created without the hierarchy

import os
import gzip
content = "Lots of content here"
outputPath = '/home/joe/file.txt.gz'
origDir = os.getcwd()
os.chdir(os.path.dirname(outputPath))
f = gzip.open(os.path.basename(outputPath), 'wb')
f.write(content)
f.close()
os.chdir(origDir)

Answer 4

It looks like you will have to use GzipFile directly:

import gzip
content = "Lots of content here"
real_f = open('/home/joe/file.txt.gz', 'wb')
f = gzip.GZipFile('file.txt.gz', fileobj=real_f)
f.write(content)
f.close()
real_f.close()

It looks like open doesn't allow you to specify the fileobj separate from the filename.