How to write a compare function for qsort from stdlib?

后端 未结 3 1055
孤城傲影
孤城傲影 2021-01-13 16:24

I have a structure:

struct pkt_
{
  double x;
  double y;
  double alfa;
  double r_kw;
};

typedef struct pkt_ pkt;

A table of these struc

相关标签:
3条回答
  • 2021-01-13 16:53

    Something like this should work:

    int porownaj(const void *p_a, const void *p_b)
    {
      /* Need to store arguments in appropriate type before using */
      const pkt *pkt_a = p_a;
      const pkt *pkt_b = p_b;
    
      /* Return 1 or -1 if alfa members are not equal */
      if (pkt_a->alfa > pkt_b->alfa) return 1;
      if (pkt_a->alfa < pkt_b->alfa) return -1;
    
      /* If alfa members are equal return 1 or -1 if r_kw members not equal */
      if (pkt_a->r_kw > pkt_b->r_kw) return 1;
      if (pkt_a->r_kw < pkt_b->r_kw) return -1;
    
      /* Return 0 if both members are equal in both structures */
      return 0;
    }
    

    Stay away from silly tricks like:

    return pkt_a->r_kw - pkt_b->r_kw;
    

    which return un-normalized values, are confusing to read, won't work properly for floating point numbers, and sometimes have tricky corner cases that don't work properly even for integer values.

    0 讨论(0)
  • 2021-01-13 17:09

    Yes, I am sorting by alfa and r_kw decides if pkt is first (first value will have the biggest (or smallest) alfa and r_kw I think). That's how I understand the problem, I am not 100% sure.

    0 讨论(0)
  • 2021-01-13 17:10

    There are two parts to the problem - how to write the code, and how to compare the packet types. You must ensure you always return a value. Your code should also always be such that:

    porownaj(&pkt_a, &pkt_b) == -porownaj(&pkt_b, &pkt_a)
    

    Your outline comparison does not handle cases such as:

    pkt_a->alfa >  pkt_b->alfa && pkt_a->r_kw <= pkt_b->r_kw
    pkt_a->alfa <  pkt_b->alfa && pkt_a->r_kw >= pkt_b->r_kw
    pkt_a->alfa == pkt_b->alfa && pkt_a->r_kw != pkt_b->r_kw
    

    There is one more problem - is it appropriate to compare floating point values for exact equality? That will depend on your application.

    Mechanically, you have to convert the const void pointers to const structure pointers. I use the explicit cast - C++ requires it, and I try to make my code acceptable to a C++ compiler even when it is really C code.

    int porownaj(const void *vp1, const void *vp2)
    {
         const pkt *pkt_a = (const pkt *)vp1;
         const pkt *pkt_b = (const pkt *)vp2;
    
         if (pkt_a->alfa >  pkt_b->alfa && pkt_a->r_kw >  pkt_b->r_kw) return 1;
         if (pkt_a->alfa == pkt_b->alfa && pkt_a->r_kw == pkt_b->r_kw) return 0;
         if (pkt_a->alfa <  pkt_b->alfa && pkt_a->r_kw <  pkt_b->r_kw) return -1;
         return 0;
     }
    

    This does not deal with the bits that I cannot resolve since I am not party to the necessary information. Note that, in general, multi-dimensional objects (such as complex numbers, or (x,y) or (x,y,z) coordinates) cannot simply be compared for greater than or less than or equal to.

    0 讨论(0)
提交回复
热议问题