How to pass spring boot argument to tomcat deployment?

Question

I have a spring boot project with packaging war stated in the pom file.

war   
...

    org.s         


        

Answer 1

You can pass context parameters to the servlet context with a context.xml. Add this as context.xml next to your pom:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE Context>
<Context>
    <Parameter
        name="spring.profiles.active"
        value="${spring.profiles.active}"
        override="false" />
</Context>

Then use the maven-war-plugin like this

<plugin>
    <groupId>org.apache.maven.plugins</groupId>
    <artifactId>maven-war-plugin</artifactId>
    <configuration>
        <containerConfigXML>context.xml</containerConfigXML>
        <filteringDeploymentDescriptors>true</filteringDeploymentDescriptors>
    </configuration>
</plugin>

Then use a profile to set the spring.profiles.active property. Spring actually will pick these up without config but somehow Spring Boot does not. For it to work in Spring Boot you can use something like this:

package com.example;

import javax.servlet.ServletContext;
import javax.servlet.ServletException;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.builder.SpringApplicationBuilder;
import org.springframework.boot.context.web.SpringBootServletInitializer;

@SpringBootApplication
public class DemoApplication extends SpringBootServletInitializer {

    private ServletContext servletContext;

    @Override
    protected SpringApplicationBuilder configure(
            SpringApplicationBuilder builder) {
        String activeProfiles =
                servletContext.getInitParameter("spring.profiles.active");
        if (activeProfiles != null) {
            builder.profiles(activeProfiles.split(","));
        }
        return builder.sources(DemoApplication.class);
    }

    @Override
    public void onStartup(ServletContext servletContext)
            throws ServletException {
        this.servletContext = servletContext;
        super.onStartup(servletContext);
    }

    public static void main(String[] args) {
        SpringApplication.run(DemoApplication.class, args);
    }

}