I have a Golang program that reads a string parameter from command line and passes it to the fmt.Sprintf function. Let\'s say tmp_str is the target string from command line.
Yes you can do it, by slicing the arguments you pass to the variadic Sprintf
function:
func TruncatingSprintf(str string, args ...interface{}) (string, error) {
n := strings.Count(str, "%s")
if n > len(args) {
return "", errors.New("Unexpected string:" + str)
}
return fmt.Sprintf(str, args[:n]...), nil
}
func main() {
tmp_str := "hello %s %s %s" // don't hesitate to add many %s here
str, err := TruncatingSprintf(tmp_str, "world") // or many arguments here
if err != nil {
fmt.Println(err)
return
}
fmt.Println(str)
}
Demonstration 1
Demonstration 2 (a different version outputting even when there's more %s than arguments)
But you don't usually use dynamic formatted strings, this isn't secure and if you want to accept any string, you should also adapt this code to no choke on %%s
. If you venture this far, then you should probably have a look at templates (which would let you use named strings, and thus the missing one wouldn't have to be the last one).
I agree with Volker's answer, but you could check your input string:
package main
import (
"fmt"
"strings"
)
func main() {
tmp_str := "hello %s"
res := tmp_str
if strings.Count(tmp_str, "%s") == 1 {
res = fmt.Sprintf(tmp_str, "world")
}
fmt.Println(res)
}
I use this one (which can probably be expanded on)
Sprintf("Hello"+"%[2]s", "World", "")
Sprintf("Hello %s"+"%[2]s", "World", "")
You cannot do this.
You have to find a different solution.
In this particular case, you could require the command line users to always supply a %s verb, and explain they can truncate the string to zero length:
Hello Friends%.0s
or even shorter:
Hello Friends%.s
The output is plain:
Hello Friends