Integer to Hexadecimal Conversion in Python

Question

a = 1
print hex(a)

The above gives me the output: 0x1

How do I get the output as 0x01 instead?

Answer 1

You can use format:

>>> "0x"+format(1, "02x")
'0x01'

Answer 2

>>> format(1, '#04x') 
'0x01'

Answer 3

You can use format :

>>> a = 1
>>> '{0:02x}'.format(a)
'01'
>>> '0x{0:02x}'.format(a)
'0x01'

Answer 4

Try:

print "0x%02x" % a

It's a little hairy, so let me break it down:

The first two characters, "0x" are literally printed. Python just spits them out verbatim.

The % tells python that a formatting sequence follows. The 0 tells the formatter that it should fill in any leading space with zeroes and the 2 tells it to use at least two columns to do it. The x is the end of the formatting sequence and indicates the type - hexidecimal.

If you wanted to print "0x00001", you'd use "0x%05x", etc.

Answer 5

Here is f-string variant for Python 3.6+:

a = 1
print(f"{a:0>2x}")

Explanation of string formatting:

• :: format specifier
• 0: fill (with 0)
• >: right-align field
• 2: width
• x: hex type

Source: 6.1.3.1 Format Specification Mini-Language

Answer 6

print "0x%02x"%a

x as a format means "print as hex".
02 means "pad with zeroes to two characters".