Python Test If Point is in Rectangle

Question

I am new to python and still learning the ropes but I am hoping someone with more experience can help me out.

I am trying to write a python script that:

Answer 1

It is better to write a separate function to do the job. Here's my function. You can just copy it if you want

def pointInRect(point,rect):
    x1, y1, w, h = rect
    x2, y2 = x1+w, y1+h
    x, y = point
    if (x1 < x and x < x2):
        if (y1 < y and y < y2):
            return True
    return False

Answer 2

This is pretty simple math. Given a rectangle with points (x1,y1) and (x2,y2) and assuming x1 < x2 and y1 < y2 (if not, you can just swap them), a point (x,y) is within that rectangle if x1 < x < x2 and y1 < y < y2. Since Python comparison operators can be chained, this is even valid Python code which should produce the correct result (in other languages you'd have to write something like x1 < x and x < x2, etc).

If you want, you can use <= instead of <. Using <= means points on the boundary of the rectangle (eg, the point (x1,y1)) count as being inside it, while using < so means such points are outside it.