I need to replicate the below API call in Robot Framework:
curl -X POST \"http://xyz/api/createApp\" -H \"Content-Type:application/json\" -d @/tmp/testfile.jso
Bulkan's robotframework-requests is nice. But if you can get by with less, you can do your own local lib/posthttp.py in a few lines like this:
import requests
import json
def do_requests_post( url=None, data=None, headers={"Content-Type":"application/json"}):
return requests.post( url, data=data, headers=json.loads(headers) )
def do_requests_request( method="GET" url=None, data=None, headers={}):
return requests.request( url, method=method, data=data, headers=json.loads(headers))
Note that the return object is the rich-and-powerful "Response" which has member functions like .json()
(which returns a dict if the .text
is sensed to be JSON) and .status_code
(int).
It perfectly works when using double backslashes and quotes like:
curl -i -H 'Accept: application/json' -H 'Content-Type: application/json' -X POST -d "{\"target\" : \"5142221345\",\"source\" : \"432567890\",\"messages\" : [ { \"format\" : \"AMR\", \"data\" : \"binarydata...\" } ]}" http://10.4.4.11:8089/v1/voice/add
http://bulkan.github.io/robotframework-requests/#Post has files parameter. And what you could do is use Get File
keyword from OperatingSystem library and pass that to your Post keyword.