Python reverse alphabetical order

Question

I have this output: [(3, \'one\'), (2, \'was\'), (2, \'two\'), (1, \'too\'), (1, \'racehorse\'), (1, \'a\')]

and i need to make it so that the tupl

Answer 1

You can use list.sort with the reverse argument:

>>> l = [(3, 'one'), (2, 'was'), (2, 'two'), (1, 'too'), (1, 'racehorse'), (1, 'a')]
>>> l.sort(key=lambda x: x[1], reverse=True)
>>> l.sort(key=lambda x: x[0])
>>> l
[(1, 'too'), (1, 'racehorse'), (1, 'a'), (2, 'was'), (2, 'two'), (3, 'one')]

Answer 2

Here you go:

from collections import Counter
from operator import itemgetter

def top5_words(text):
  tally = Counter()
  for word in text.split():
      tally[word] += 1
  vals = tally.items()
  vals.sort(key=itemgetter(0))
  vals.sort(key=itemgetter(1), reverse=True)
  return vals

print top5_words("one one was a racehorse two two was one too")
# [('one', 3), ('two', 2), ('was', 2), ('a', 1), ('racehorse', 1), ('too', 1)]

Answer 3

Define the list:

>>> mylist = [(3, 'one'), (2, 'was'), (2, 'two'), (1, 'too'), (1, 'racehorse'), (1, 'a')]

Sort the list:

>>> sorted(mylist, key=lambda x: (-x[0], x[1]), reverse=True)
[(1, 'too'), (1, 'racehorse'), (1, 'a'), (2, 'was'), (2, 'two'), (3, 'one')]