List all subclasses with fully qualified names

后端 未结 4 701
北海茫月
北海茫月 2021-01-13 08:18

I would like to get a list of all subclasses of a given class with their fully qualified names. I wanted to copy it from Eclipse and paste into a text file like this:

<
相关标签:
4条回答
  • 2021-01-13 08:30

    nWire for Java can give you the complete list of classes which extend a given class or implement a specific interface. You will get it in the nWire navigator, which does not provide a copy command.

    However, you can tap into the nWire database, which is a standard H2 database and has a very simple structure, and get everything you need with a simple query. We will be introducing reporting capabilities some time in the future.

    IMHO, it will be less of an effort and you'll get a tool which gives you a lot more.

    0 讨论(0)
  • 2021-01-13 08:33

    The method in the Hierarchy view which does build the hierarchy tree is in the org.eclipse.jdt.internal.ui.typehierarchy.TypeHierarchyLifeCycle:

    private ITypeHierarchy createTypeHierarchy(IJavaElement element, IProgressMonitor pm) throws JavaModelException {
        if (element.getElementType() == IJavaElement.TYPE) {
            IType type= (IType) element;
            if (fIsSuperTypesOnly) {
                return type.newSupertypeHierarchy(pm);
            } else {
                return type.newTypeHierarchy(pm);
            }
        } else {
    

    Which uses org.eclipse.jdt.internal.core.SourceType class

    /**
     * @see IType
     */
    public ITypeHierarchy newTypeHierarchy(IJavaProject project, IProgressMonitor monitor) throws JavaModelException {
        return newTypeHierarchy(project, DefaultWorkingCopyOwner.PRIMARY, monitor);
    }
    

    So if you can get a IJavaElement, you can check those classes to emulate the same result.

    It uses a org.eclipse.jdt.internal.core.CreateTypeHierarchyOperation

    0 讨论(0)
  • 2021-01-13 08:39

    Update: my original answer wouldn't work as there is no context to the structured selection.

    This answer shows how to contribute the action to the context menu and retrieve the structured selection. You can modify that type's execute method to process the Hierarchy (as VonC suggests, +1) and obtain all the sub-types and set the content to the clipboard as follows:

    public Object execute(ExecutionEvent event) throws ExecutionException {
        IWorkbenchPart activePart = HandlerUtil.getActivePart(event);
        try {
            IStructuredSelection selection = SelectionConverter
                    .getStructuredSelection(activePart);
    
            IJavaElement[] elements = SelectionConverter.getElements(selection);
    
            if (elements != null && elements.length > 0) {
                if (elements[0] != null && elements[0] instanceof IType) {
                    IType type = (IType)elements[0];
    
                    ITypeHierarchy hierarchy =
                        type.newTypeHierarchy(new NullProgressMonitor());
    
                    IType[] subTypes = hierarchy.getAllSubtypes(type);
    
                    StringBuffer buf = new StringBuffer();
                    for (IType iType : subTypes) {
                        buf.append(iType.getFullyQualifiedName()).append("\n");
                    }
    
                    Shell shell = HandlerUtil.getActiveShell(event);
    
                    Clipboard clipboard = new Clipboard(shell.getDisplay());
    
                    clipboard.setContents(
                        new Object[]{buf.toString()}, 
                        new Transfer[]{TextTransfer.getInstance()});
                }
            }
        } catch (JavaModelException e) {
            logException(e);
        }
        return null;
    }
    
    0 讨论(0)
  • 2021-01-13 08:55

    Following the pattern described in http://internna.blogspot.com/2007/11/java-5-retrieving-all-classes-from.html one can do it programmatically. It's a shame Eclipse can't do it OOTB. Doing it in Java code allows to do the filtering with no additional cost (e.g. !(klazz.isEnum())).

    0 讨论(0)
提交回复
热议问题