Xcode, Swift; Detect hyperlink click in UIWebView

Question

I made an iOS app with Xcode and Swift.

I want to open specific hyperlinks in Safari browser, there others in the WebView itself.

To reach this, I\'ll have t

Answer 1

please try

for swift 3.0

 public func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool
        {
         if navigationType == .linkClicked
         {

            }
            return true;
        }

swift 2.2

internal func webView(webView: UIWebView, shouldStartLoadWithRequest request: NSURLRequest, navigationType: UIWebViewNavigationType) -> Bool
    {
        if navigationType == .LinkClicked
        {

        }
        return true;
    }

Answer 2

This is the working solution (Xcode 7.3.1 and Swift 2.2):

func webView(webView: UIWebView, shouldStartLoadWithRequest request: NSURLRequest, navigationType: UIWebViewNavigationType) -> Bool {

    if request.URL?.query?.rangeOfString("target=external") != nil {
        if let url = request.URL {
            UIApplication.sharedApplication().openURL(url)
            return false
        }
    }
    return true
}

Many thanks to danhhgl from freelancer.com!

Answer 3

I think you can solve with this code:

 function reportBackToObjectiveC(string)
 {
 var iframe = document.createElement("iframe");
 iframe.setAttribute("src", "callback://" + string);
 document.documentElement.appendChild(iframe);
 iframe.parentNode.removeChild(iframe);
 iframe = null;
 }

var links = document.getElementsByTagName("a");
for (var i=0; i<links.length; i++) {
links[i].addEventListener("click", function() {
    reportBackToObjectiveC("link-clicked");
}, true);
}

in ios code:

if ([[[request URL] scheme] isEqualToString:@"callback"]) {
[self setNavigationLeavingCurrentPage:YES];
return NO;
}

More details you can check from here: