I\'m trying to use the LIKE keyword with the % wildcards wrapping the parameter, but I\'m not sure how to get the % characters into the statement without breaking it. Right
The % characters have to be in the search string...
SET @search = '%' + @search + '%'
SET @SQLQuery = 'SELECT * FROM [tblApps] WHERE [firstName] LIKE @search'
Note that the following would also work, but introduces potential for a SQL injection vulnerability...
-- DON'T do this!
SET @SQLQuery = 'SELECT * FROM [tblApps] WHERE [firstName] LIKE ''%' + @search + '%'''
SET @search = '%' + @search
SET @SQLQuery = 'SELECT * FROM [tblApps] WHERE [firstName] LIKE ' + @search + '%'
declare @Cmd nvarchar(2000)
declare @eName varchar(10)
set @eName='a'
set @Cmd= 'select * from customer1 where name LIKE '''+'%' +@eName+ '%' + ''''
print @Cmd
EXECUTE sp_executesql @Cmd
This worked for me!
SET @search = '''%' + @search + '%'''
SET @SQLQuery = 'SELECT * FROM [tblApps] WHERE [firstName] LIKE' + @search
EXEC sp_executesql @SQLQuery
SET @SQLQuery = 'SELECT * from [tblApps] WHERE [firstName] LIKE ''%'' + @search + ''%'''
exec sp_executesql @query=@SQLQuery, @params=N'@search nvarchar(96)', @search=@search
The only difference from this version as compared to the others is that the dynamic execution of the sql is in fact parameterized which mitigates sql injection a bit.