发表新帖
发表新帖

How to get html() from element excluding another element?

后端 未结
关注
2 1721
庸人自扰
庸人自扰 2021-01-13 06:21

Sorry for real stupid question. But it does not work either way.
相关标签:
2条回答
  • 猫巷女王i
    2021-01-13 06:29

    This should do it:

    var clone = $('div.content').clone();
clone.find('.dontgrab').remove();

var html = clone.html();
    0 讨论(0)
  • 滥情空心
    2021-01-13 06:50

    I think you are trying to do:

    var htmlcontent = $('.content').remove(".dontgrab").html();

    You could use .not() if the situation was like:

    var htmlcontent = $('div').not(".dontgrab").html();

<body>
<div class="content">
  BEFORE  

  AFTER
</div>
<div class="content dontgrab">DON'T GRAB</div>
</body>

    I dont think you can use .not for selected elements children. I hope it helps

    0 讨论(0)
 看不清?
提交回复
热议问题