Python how to remove last comma from print(string, end=“, ”)

Question

my output from a forloop is

string = \"\"
for x in something:
   #some operation
   string =  x += string 

print(string)

5
66
777

I use

Answer 1

In case your for loop is doing also something else than printing, then you can maintain your current structure with this approach.

 strings = ['5', '66', '777']

 for i in range(len(strings)-1):
      # some operation

      print(strings[i], end=', ')

 # some operation (last time)
 print(strings[-1])

5, 66, 777

Answer 2

You could build a list of strings in your for loop and print afterword using join:

strings = []

for ...:
   # some work to generate string
   strings.append(sting)

print(', '.join(strings))

alternatively, if your something has a well-defined length (i.e you can len(something)), you can select the string terminator differently in the end case:

for i, x in enumerate(something):
   #some operation to generate string

   if i < len(something) - 1:
      print(string, end=', ')
   else:
      print(string)

UPDATE based on real example code:

Taking this piece of your code:

value = input("")
string = ""
for unit_value in value.split(", "):
    if unit_value.split(' ', 1)[0] == "negative":
        neg_value = unit_value.split(' ', 1)[1]
        string = "-" + str(challenge1(neg_value.lower()))
    else:
        string = str(challenge1(unit_value.lower()))

    print(string, end=", ")

and following the first suggestion above, I get:

value = input("")
string = ""
strings = []
for unit_value in value.split(", "):
    if unit_value.split(' ', 1)[0] == "negative":
        neg_value = unit_value.split(' ', 1)[1]
        string = "-" + str(challenge1(neg_value.lower()))
    else:
        string = str(challenge1(unit_value.lower()))

    strings.append(string)

print(', '.join(strings))

Answer 3

If you can first construct a list of strings, you can then use sequence unpacking within print and use sep instead of end:

strings = ['5', '66', '777']

print(*strings, sep=', ')

5, 66, 777

Answer 4

l = [5, 66, 777]
print('{0}, {1}, {2}'.format(*l))

Answer 5

list_1 = [5, 10, 15, 20]

new_list = []
[ new_list.append(f'({i}*{i+5})') for i in list_1 ] 
print(*new_list,sep="+") 

Output

(5*10)+(10*15)+(15*20)+(20*25)