I have the following functions to generate md5-hashes for files. The functions work great for small files, but crashes and generate Run-time error 7 - Out of memory<
It looks like you reached the memory limit. A better way would be to compute the MD5 of the file by block:
Public Function ComputeMD5(filepath As String) As String
Dim buffer() As Byte, svc As Object, hFile%, blockSize&, i&
blockSize = 2 ^ 16
' open the file '
If Len(Dir(filepath)) Then Else Err.Raise 5, , "file not found" & vbCr & filepath
hFile = FreeFile
Open filepath For Binary Access Read As hFile
' allocate buffer '
If LOF(hFile) < blockSize Then blockSize = ((LOF(hFile) + 1024) \ 1024) * 1024
ReDim buffer(0 To blockSize - 1)
' compute hash '
Set svc = CreateObject("System.Security.Cryptography.MD5CryptoServiceProvider")
For i = 1 To LOF(hFile) \ blockSize
Get hFile, , buffer
svc.TransformBlock buffer, 0, blockSize, buffer, 0
Next
Get hFile, , buffer
svc.TransformFinalBlock buffer, 0, LOF(hFile) Mod blockSize
buffer = svc.Hash
' cleanup '
svc.Clear
Close hFile
' convert to an hexa string '
ComputeMD5 = String$(32, "0")
For i = 0 To 15
Mid$(ComputeMD5, i + i + 2 + (buffer(i) > 15)) = Hex(buffer(i))
Next
End Function
This is an extension to FlorentB's answer, which worked brilliantly for me until my files surpassed the 2GB LOF() size limit.
I tried to adapt for getting file length by alternate means as follows:
Public Function ComputeMD5(filepath As String) As String
If Len(Dir(filepath)) Then Else Err.Raise 5, , "File not found." & vbCr & filepath
Dim blockSize As Long: blockSize = 2 ^ 20
Dim blockSize_f As Double
Dim buffer() As Byte
Dim fileLength As Variant
Dim hFile As Integer
Dim n_Reads As Long
Dim i As Long
Dim svc As Object: Set svc = CreateObject("System.Security.Cryptography.MD5CryptoServiceProvider")
fileLength = DecGetFileSize(filepath)
If fileLength < blockSize Then blockSize = ((fileLength + 1024) \ 1024) * 1024
ReDim buffer(0 To blockSize - 1)
n_Reads = fileLength / blockSize
blockSize_f = fileLength - (CDbl(blockSize) * n_Reads)
hFile = FreeFile
Open filepath For Binary Access Read As hFile
For i = 1 To n_Reads
Get hFile, i, buffer
svc.TransformBlock buffer, 0, blockSize, buffer, 0
Next i
Get hFile, i, buffer
svc.TransformFinalBlock buffer, 0, blockSize_f
buffer = svc.Hash
svc.Clear
Close hFile
ComputeMD5 = String$(32, "0")
For i = 0 To 15
Mid$(ComputeMD5, i + i + 2 + (buffer(i) > 15)) = Hex(buffer(i))
Next
End Function
Public Function DecGetFileSize(fname As String) As Variant
Dim fso As New FileSystemObject
Dim f: Set f = fso.GetFile(fname)
DecGetFileSize = CDec(f.Size)
Set f = Nothing
Set fso = Nothing
End Function
This all runs fine, returning a string, however that string does not equal the MD5 calculated using other tools on the same file.
I can't work out where the discrepancy is originating.
I've checked and double checked filelength, n_reads, blockSize and blockSize_f and I'm sure those values are all correct.
I had some trouble with the Get function, where if I didn't explicitly tell it the block number, it dies at block 2048.
Any ideas / pointers would be much appreciated.