SWIFT: Why is “NSURL(string:” returning with Nil, even though it's a valid url in a browser?

Question

The first two example links are working the third one returns NIL.

Why is NSUrl returning nil for such string, even though it\'s a valid url in a browser?

Am

Answer 1

In iOs 9:

myString = myString.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())!

Hope it helps

Answer 2

You should URL-encode the URL like this:

selectedFeedUrl = selectedFeedUrl.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)

Answer 3

For swift3 you can do like this

let url = URL(string:url.addingPercentEncoding(withAllowedCharacters: NSCharacterSet.urlQueryAllowed)!)!

Answer 4

Thank you guys for your help. I added these two lines to my code and it works now:

    selectedFeedURL = selectedFeedURL.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!
    selectedFeedURL =  selectedFeedURL.stringByReplacingOccurrencesOfString("%09%09", withString:"")